Air at 0`C and a pressure of 100 kPa occupies a volume of 1 liter. At what temperature will

Air at 0`C and a pressure of 100 kPa occupies a volume of 1 liter. At what temperature will the volume of air be equal to 3 liters and when the pressure doubles?

To find the value of the required temperature of the taken air, we use the proportion: Pk * Vk / Tk = Pn * Vn / Tn, from where we express: Tk = Pk * Vk * Tn / Pn * Vn.

Variables: Pк (final pressure) = 2Рн (initial pressure); Vк – considered volume (Vк = 3 l); Тн – initial temperature (Тн = 0 ºС = 273 К); Vн – initial volume (Vн = 1 l).

Let’s calculate: Tk = 2Pn * 3 * 273 / Pn * 1 = 1638 K (1365 ºС).

Answer: The volume of air taken will be 3 liters at a temperature of 1365 ºС.