Air at a temperature of 25 degrees Celsius and under a pressure of 150 kPa in a container with a volume of 1 liter.

Air at a temperature of 25 degrees Celsius and under a pressure of 150 kPa in a container with a volume of 1 liter. What work does air do in an isobaric process if the temperature rises by 30 degrees Celsius?

To find the value of the work done by the taken air during the isobaric process, we use the formula: A = P * ΔV = P * (Vk – Vn) = P * (Vn * Tk / Tn – Vn) = P * (Vn * (Tn + ΔT ) / Tn – Vn).

Data: P – pressure (P = 150 kPa = 15 * 10 ^ 4 Pa); Vн – volume before expansion (Vн = 1 l = 10 ^ -3 m3); Тн – initial temperature (Тн = 25 ºС = 298 К); ΔТ – temperature rise (ΔТ = 30 ºС).

Let’s perform the calculation: A = 15 * 10 ^ 4 * (10 ^ -3 * (298 + 30) / 298 – 10 ^ -3) = 15.1 J.

Answer: The work of the taken air is 15.1 J.