Air with a volume of 1.45 m3 at a temperature of 20 ºC and a pressure of 100 kPa was turned into a liquid state.

| August 12, 2021 | education

Air with a volume of 1.45 m3 at a temperature of 20 ºC and a pressure of 100 kPa was turned into a liquid state. What volume will liquid air take if its density is 861 kg / m3.

To find the value of the volume occupied by liquid air, we use the formula: V2 = m / ρ = P * V1 * M / (R * T * ρ).

Constants and variables: P – pressure (P = 100 kPa = 10 ^ 5 Pa); V1 – volume in the gaseous state (V1 = 1.45 m3); M is the molar mass of air (M = 29 * 10 ^ -3 kg / mol); R – universal gas constant (R = 8.314 J / (K * mol)); T – air temperature (T = 293 K (20 ° C)); ρ is the density of liquid air (according to the condition ρ = 861 kg / m3).

Let’s calculate: V2 = P * V1 * M / (R * T * ρ) = 10 ^ 5 * 1.45 * 29 * 10 ^ -3 / (8.314 * 293 * 861) = 2 * 10 ^ -3 m3 = 2 p.

Answer: In a liquid state, air should take up a volume of 2 liters.



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