All bodies are 6 N, its volume is 400 cm3. Will the body drown in water? Alcohol? Kerosene?

Given:

P = 6 Newton – body weight in air;

V = 400 cubic centimeters = 0.0004 cubic meters – body volume;

g = 9.8 Newton / kilogram – acceleration of gravity;

ro1 = 1000 kg / m3 – water density;

ro2 = ro3 = 800 kg / m3 – density of alcohol and kerosene.

It is required to determine whether the body will drown in water, alcohol and kerosene.

Determine the body weight:

m = P / g = 6 / 9.8 = 0.612 kilograms.

Then the density of the body will be equal to:

ro = m / V = ​​0.612 / 0.0004 = 1530 kg / m3.

Since ro> ro1> ro2 = ro3 (1530> 1000> 800), the body will drown in water, kerosene and alcohol.

Answer: since the density of the body is greater than the density of liquids, the body will drown in water, kerosene and alcohol.