Allocate the volume of air used to burn 50 liters of ethylene.
| February 4, 2021 | education
Combustion of ethylene:
С2Н4 + 3 О2 = 2 СО2 + 2 Н2О
It can be seen from the equation that for the combustion of 1 ethylene molecule, 3 oxygen molecules are needed.
According to Avogadro’s law: if 50 liters of ethylene are burned, then 150 liters of oxygen will be consumed (three times more).
The air contains 21% oxygen.
We calculate the volume of air:
150l * 100% / 21% = 714.3 l
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