Along the sides of the right angle, starting from its top, two bodies move simultaneously: one at a speed of 24

Along the sides of the right angle, starting from its top, two bodies move simultaneously: one at a speed of 24 meters per minute, the other at 10 meters per minute. In how many minutes will the distance between the bodies be 806 m?

Since we have a right angle, the speed of separation between the bodies will be hypotenuse.

It is the sum of the squares of two legs.

In this case, it will be:

A ^ 2 = 10 ^ 2 + 24 ^ 2.

A ^ 2 = 100 + 576 = 676.

A = 26 m / min.

We find the time during which 806 meters are formed between the bodies.

To do this, we divide the indicated distance by the distance speed.

As a result, we get:

806/26 = 31 minutes.

Answer:

The distance between the bodies will be 806 meters in 31 minutes after the start of movement.



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