Aluminum and steel balls having the same mass and initial temperature (specific heat capacity of steel 460 J / kg
Aluminum and steel balls having the same mass and initial temperature (specific heat capacity of steel 460 J / kg * deg, aluminum 920 J / kg * deg) were lowered into the hot water of the vessel. Will their temperature change be the same? Will the balls absorb the same amount of heat?
Data: The mass and initial temperature of the balls are the same.
Constants: C1 (specific heat capacity of aluminum) = 920 J / (kg * ºС); C2 (specific heat capacity of steel) = 460 J / (kg * ºС).
1) Heat transfer between bodies lasts until thermodynamic equilibrium is established → balls and water after heat exchange will have the same temperature.
2) The absorbed amount of heat: Q = Cx * m * Δt, since m1 = m2 and Δt1 = Δt2, then the aluminum ball will absorb 2 times more heat: Q1 / Q2 = C1 / C2 = 920/460 = 2.
Answer: the temperature change is the same, the amount of heat absorbed by an aluminum ball is 2 times greater than that of a steel ball