Aluminum reacts with dilute sulfuric acid according to the scheme: Al + H2SO4 – Al2 (SO4) 3 + H2

Aluminum reacts with dilute sulfuric acid according to the scheme: Al + H2SO4 – Al2 (SO4) 3 + H2. Determine the volume of the formed hydrogen if 3, 01 * 10 (to the 23rd power) of aluminum atoms have reacted.

Metallic aluminum interacts with sulfuric acid. This produces aluminum sulfate and releases hydrogen gas. The interaction is described by the following chemical equation.

2Al + 3H2SO4 = Al2 (SO4) 3 + 3 H2;

Let’s calculate the chemical amount of aluminum. To do this, we divide the available number of aluminum molecules by the number of molecules in 1 mole of aluminum.

M Al = 27 grams / mol;

N Al = (3.01 x 1023) / (6.02 x 1023) = 0.5 mol;

The chemical amount of released hydrogen will be: 0.5 x 3/2 = 0.75 mol

Let’s define its volume.

To do this, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 0.75 x 22.4 = 16.8 liters;