Aluminum weighing 15 g interacts with sulfuric acid. Determine the mass of salt.

We need to find a lot of salt.

At the same time, we know that aluminum that interacts with sulfuric acid has a mass of 15 grams.

First, we need to write an equation:

2Al + 3H2SO4 = Al2 (SO4) 3 + 3H2;

In our equation, salt is Al2 (SO4) 3.

To find the mass of salt, you need to know the molar mass of Al and salt.

Al = 27 g / mol.

Al2 (SO4) 3 = 2 * 27 + (32 + (16 * 4)) * 3 = 54 + (32 + 64) * 3 = 54 + 96 * 3 = 54 + 288 = 342 g / mol.

Now let’s make the proportion.

15 g – x g

2 * 27 g / mol – 342 g / mol

Find x:

(15 * 342): 54 = 5130/54 = 95 g.

Answer: the mass of salt is 95 g.