Aluminum weighing 5.4 g reacted with sulfur. Find the mass of the resulting salt.

univerkov | February 16, 2021 | education

Aluminum with sulfur forms aluminum sulfide.
2Al + 3S = Al2S3.
Let’s determine the number of moles of aluminum and its salt.
n (Al) = m / Mr = 5.4 g / 27 g / mol = 0.2 mol.
n (Al2S3) = n (Al) / 2 = 0.2 mol / 2 = 0.1 mol.
The salt mass will be equal.
m (Al2S3) = 0.1 mol * 150.16 g / mol = 15.02 g.

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