Ammonia (NH3) V = 560 ml was dissolved in water weighing 600 g. Determine the mass fraction

Ammonia (NH3) V = 560 ml was dissolved in water weighing 600 g. Determine the mass fraction of ammonia in the resulting solution

1) find the amount of ammonia in ph-le: n (mol) = V (l) / Vm (l / mol); Vm = 22.4 l / mol for normal conditions; n (NH3) = 0.56 / 22.4 = 0.025 mol;
2) find the mass of ammonia by f-le: m (g) = n (mol) * M (g / mol); M (NH3) = 17 g / mol; m (NH3) = 0.025 * 17 = 0.425 g;
3) find the masses. the proportion (w) of ammonia in f-le: w = [m (NH3) / (m (NH3) + m (H2O))] * 100%; w = [0.425 / (0.425 + 600)] * 100% = 0.071%;
Answer: w (NH3) = 0.071%;