Ammonia was passed through 175 g of a sulfuric acid solution with a mass fraction

Ammonia was passed through 175 g of a sulfuric acid solution with a mass fraction of 14% to form ammonium sulfate. Calculate the volume of the reacted gas.

Given:
m solution (H2SO4) = 175 g
ω (H2SO4) = 14%

Find:
V (NH3) -?

Solution:
1) H2SO4 + 2NH3 => (NH4) 2SO4;
2) M (H2SO4) = Mr (H2SO4) = Ar (H) * N (H) + Ar (S) * N (S) + Ar (O) * N (O) = 2 * 1 + 32 * 1 + 16 * 4 = 98 g / mol;
3) m (H2SO4) = ω (H2SO4) * m solution (H2SO4) / 100% = 14% * 175/100% = 24.5 g;
4) n (H2SO4) = m (H2SO4) / M (H2SO4) = 24.5 / 98 = 0.25 mol;
5) n (NH3) = n (H2SO4) = 0.25 * 2 = 0.5 mol;
6) V (NH3) = n (NH3) * Vm = 0.5 * 22.4 = 11.2 liters.

Answer: The NH3 volume is 11.2 liters.