Ammonia weighing 85 g was passed through nitric acid. What is the mass of the salt obtained

Ammonia weighing 85 g was passed through nitric acid. What is the mass of the salt obtained if its yield is 90% of the theoretical?

1. Let’s compose the reaction equation:

NH3 + HNO3 = NH4NO3

2. Find the masses of NH3 and NH4NO3 by the formula: m = n * M (according to the equation, all substances are taken by 1 mol)

m (NH3) = 1 mol * (14 + 1 * 3) = 17 g

m (NH4NO3) = 1 mol * (14 + 1 * 4 + 14 + 16 * 3) = 80 g

3. Let’s calculate the theoretical yield of NH4NO3, making the proportion:

85 g NH3 – x g NH4NO3

17 g NH3 – 80 g NH4NO3

Hence, x = 85 * 80/17 = 400 g

4. Let’s find a practical way out:

400 g NH4NO3 – theoretical yield – 100%

x g NH4NO3 – practical yield – 90%

Hence, x = 400 * 90/100 = 360 g.