Ammonia with a volume of 5.6 L was mixed with 6.72 L of hydrogen chloride. Determine the mass of the formed salt.

When ammonia reacts with hydrochloric acid, a salt is formed – ammonium chloride.
NH3 + HCl = NH4Cl.
Let us determine the number of moles of gases.
n (NH3) = V / Vm = 5.6 L / 22.4 mol / L = 0.25 mol.
n (HCl) = 6.72 L / 22.4 mol / L = 0.3 mol.
Acid in excess, the calculation is carried out for ammonia.
If from 22.4 liters of ammonia 53.5 g of salt is formed, then from 5.6 liters of ammonia – x g.
The mass of salt will be equal.
m (NH4Cl) = 5.6 L * 53.5 g / 22.4 mol / L = 13.38 g.