An active resistance of 50 Ohm is included in the AC circuit with an effective voltage value of 220 V.

An active resistance of 50 Ohm is included in the AC circuit with an effective voltage value of 220 V. Find the effective and peak value of the current?

Given:
U = 220 V;
R = 50 ohms.
Decision:
Based on the fact that in an alternating current circuit, where there is an active resistance, phase current fluctuations always coincide with voltage fluctuations.
To find the current strength, you need to use this formula:
Ohm’s formula: I = U / R.
You also need a formula for the amplitude value of the current strength: Im = root of 2 * I.
Substitute the values we know into the formula.
I = 220/50 = 22/5 = 4.4 A.
Im = 4.4 * root of 2 = 6.16 A.
Answer: I = 4.4 A; Im = 6.16 A