An acute angle AOC is given. Point D lies between points O and A, point B – between points O and C.

An acute angle AOC is given. Point D lies between points O and A, point B – between points O and C. It is known that OA = OC and the angle OAB is equal to the angle OCD. Prove that triangles OAB and OCD are equal. Find side AB if side DC = 15 cm

Triangles AOB and OCD are equal, since they have the same sides AO and OC, and two angles adjacent to the side coincide (common angle O and two known equal specified angles). Since the triangles are equal, AB = CD = 15 cm.



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