An aircraft weighing 100 tons took off to an altitude of 1 km at a speed of 200 m / s.

An aircraft weighing 100 tons took off to an altitude of 1 km at a speed of 200 m / s. What is its mechanical energy relative to the Earth?

According to the law of conservation of energy, the mechanical energy of the aircraft:
E = Eк + Eп, where Eк – kinetic energy, Eп – potential energy.
Eк = (m * V ^ 2) / 2, where m is the mass of the aircraft (m = 100 t = 100,000 kg), V is the speed of the aircraft (V = 200 m / s).
Ep = m * g * h, where g is the acceleration of gravity (g = 10 m / s ^ 2), h is the aircraft height above the ground (h = 1 km = 1000 m).
E = Eк + Ep = (m * V ^ 2) / 2 + m * g * h = (100000 * 200 ^ 2) / 2 + 100000 * 10 * 1000 = 3 * 10 ^ 9 J = 3 GJ.
Answer: The mechanical energy of the aircraft is 3 GJ.