An aircraft weighing 2 tons, flying up to the airfield, reduced its speed from 50 to 30 m / s.

An aircraft weighing 2 tons, flying up to the airfield, reduced its speed from 50 to 30 m / s. Find the change in momentum of the plane.

Given: m (the mass of the aircraft under consideration) = 2 t (in the SI system m = 2 * 10 ^ 3 kg); V0 (initial speed) = 50 m / s; V (final speed) = 30 m / s.

The change in the momentum of the considered aircraft is determined by the formula: ΔP = m * (V – V0).

Let’s calculate: ΔP = 2 * 10 ^ 3 * (30 – 50) = -40 * 10 ^ 3 kg * m / s.

Answer: The momentum of the aircraft in question has decreased by 40 * 103 kg * m / s.