An airplane weighing 100 tons takes off to a height of 1 km at a speed of 200 m / s.

An airplane weighing 100 tons takes off to a height of 1 km at a speed of 200 m / s. What is its mechonic inertia relative to the ground?

m = 100 t = 100000 kg.

h = 1 km = 1000 m.

g = 10 N / kg.

V = 200 m / s.

E -?

The mechanical energy of an airplane E is the sum of its potential Ep and kinetic energy Ek: E = En + Ek.

The potential energy of an aircraft Еп with mass m, which is located at a height h above the earth’s surface, is determined by the formula: Еп = m * g * h, where g is the acceleration of gravity.

Ep = 100000 kg * 10 N / kg * 1000 m = 1 * 10 ^ 9 J.

We express the kinetic energy of the aircraft Ek by the formula: Ek = m * V2 / 2, where V is the speed of its movement.

Ek = 100000 kg * (200 m / s) ^ 2/2 = 2 * 10 ^ 9 J.

E = 1 * 10 ^ 9 J + 2 * 10 ^ 9 J = 3 * 10 ^ 9 J.

Answer: the mechanical energy of the aircraft is E = 3 * 10 ^ 9 J.