An alkene weighing 0.84 g adds 1.6 g of bromine. Determine the alkene formula.

Let x-СnH2n, m = 0.84
160 g = Br2, m = 1.6 g
СnH2n + Br2 = CnH2nBr2
x = 160 * x * 0.84 / 1.6 = 84 g
M (Br2) = 160 g / mol
12n + 2n = 84
n = 6
C6H12



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