An alloy of gold and silver containing 110 grams of gold was fused with 100 grams of pure gold.

An alloy of gold and silver containing 110 grams of gold was fused with 100 grams of pure gold. As a result, the gold content in the alloy increased by 20% compared to the original. How much silver is in the alloy?

Decision.
Let’s find how many percent of gold the original alloy contains, for this we will compose the proportion:
110 / x = 210 / (x + 20).
Let’s solve the equation:
210x = 110 (x + 20);
210x = 110x + 110 20;
210x = 110x + 2200;
210x-110x = 2200;
100x = 2200;
x = 22% – the percentage of gold in the original alloy.
100% -22% = 78% is the percentage of silver in the original alloy.
22% + 20% = 42% – the percentage of gold in the new alloy.
100% -42% = 58% – the percentage of silver in the new alloy.
Answer: 58% silver in the new alloy.



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