An alternating voltage is applied to the electrodes of the vacuum diode, as a result of which the current flowing

| August 11, 2021 | education

An alternating voltage is applied to the electrodes of the vacuum diode, as a result of which the current flowing through this diode evenly increases in 2 μs from 0 to 12 A. Determine the amount of charge that has passed through the diode during this time.

t = 2 μs = 2 * 10 ^ -6 s.
Io = 0 A.
I = 12 A.
Q -?
According to the definition, the strength of the current I is the electric charge Q that has passed through the conductor per unit of time t.
I = Q / t.
Let us express the amount of charge: Q = I * t.
For alternating voltage, when the current strength varies from 0 to 12 A, then the average value of the current strength Iav = (I – Io) / 2 must be taken into the formula.
Q = Iav * t = (I – Io) * t / 2.
Q = (12 A – 0 A) * 2 * 10 ^ -6 s / 2 = 12 * 10 ^ -6 Cl.
Answer: a charge of Q = 12 * 10 ^ -6 C passed through the diode.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.