An aluminum ball falls onto the sand from a height of 25 m.

An aluminum ball falls onto the sand from a height of 25 m. How many degrees will the shark heat up if half of its potential energy has passed into its internal energy?

Data: h (drop height of the aluminum ball) = 25 m; η (percentage of the potential energy of the ball that goes into heating) = 50% (0.5).

Constants: g (acceleration due to gravity) ≈ 10 m / s2; Ca (specific heat capacity of aluminum) = 920 J / (kg * ºС).

The increase in the temperature of the aluminum ball is determined from the formula: η = Q / Ep = C * m * Δt / (m * g * h) = C * Δt / (g * h), whence Δt = g * h * η / С.

Calculation: Δt = 10 * 25 * 0.5 / 920 ≈ 0.136 ºС.

Answer: The temperature of the aluminum ball will increase by 0.136 ºС.



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