An aluminum bar weighing 500 g at a temperature of 20 degrees transferred the amount of heat Q = 900 kJ.
An aluminum bar weighing 500 g at a temperature of 20 degrees transferred the amount of heat Q = 900 kJ. what will be the temperature of aluminum?
m = 500 g = 0.5 kg.
Ca = 920 J / kg * ° C.
t1 = 20 ° C.
Q = 900 J.
t2 -?
The amount of thermal energy Q that goes to heat the body is determined by the formula: Q = Ca * m * (t2 – t1), where Ca is the specific heat capacity of the substance from which the body is made, m is the body weight, t2, t1 are the final and initial temperatures body when heated.
Q = Ca * m * t2 – Ca * m * t1.
Ca * m * t2 = Q + Ca * m * t1.
t2 = (Q + Cа * m * t1) / Cа * m.
According to the table of specific heat capacity of substances, the specific heat capacity of aluminum is Ca = 920 J / kg * ° C.
t2 = (900 J + 920 J / kg * ° C * 0.5 kg * 20 ° C) / 920 J / kg * ° C * 0.5 kg = 22 ° C.
Answer: the aluminum bar will heat up to a temperature of t2 = 22 ° C.
