An aluminum block weighing 3 kg lies On a horizontal steel plate, the coefficient of friction

| March 11, 2021 | education

An aluminum block weighing 3 kg lies On a horizontal steel plate, the coefficient of friction of aluminum about Steel is 0.61. If the bar is acted upon in the horizontal direction by a force equal to 17 Newtons, then the bar …

m = 3 kg.

g = 9.8 m / s2.

μ = 0.61.

F = 17 N.

Ftr -?

The sliding friction force Ftr is determined by the formula: Ftr = μ * N, where μ is the sliding friction coefficient, N is the force with which the bar is pressed against the surface.

Force N is equal to the weight of the body: N = m * g.

Ftr = μ * m * g.

Ftr = 0.61 * 3 kg * 9.8 m / s2 = 17.94 N.

The sliding friction force is Ftr = 17.94 N.

In order for the bar to begin to move, a force greater than the sliding friction force must act on it. Since the force F = 17 N <Ftr = 17.94 N acts on it, the body will be at rest.

Answer: the body will not budge.



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