An aluminum pan with a mass of 100 g with 2 liters of water is heated from 10 s to 90 s how much heat is spent on this?

Let’s write down the heat balance equation: Q1 + Q2-Q = 0, where Q1 and Q2 are the amount of heat received by the water and the pan, respectively; Q – the amount of heat spent on heating the pot with water.
Express from the equation Q: Q = Q1 + Q2
Q1 = c1 * m1 * t1; Q2 = c2 * m2 * t2
t1 = t2 = t = 90-10 = 80 (degrees Celsius)
m2 = p * V = 1000 * 2 * 10 ^ -3 = 2 (kg)
Q = t * (c1 * m1 + c2 * m2) = 80 * (920 * 0.1 + 4200 + 2) = 679360 (J)
Answer: 679360 J