An aluminum saucepan weighing 0.2 kg contains water with a volume of 0.5 liters and ice weighing 200

An aluminum saucepan weighing 0.2 kg contains water with a volume of 0.5 liters and ice weighing 200 grams at a temperature of 0 degrees. The pan is heated on a 600 watt hot plate for 30 minutes. How much water has boiled away if the tile efficiency is 50%?

Given: m1 (pan) = 0.2 kg; V2 (water) = 0.5 l (m2 = 0.5 kg); m3 (ice) = 200 g (0.2 kg); t0 = 0 ºС; N = 600 W; t = 30 min (1800 s); η = 50%.

λ (ice) = 3.4 * 10 ^ 5 J / kg; C1 (aluminum) = 920 J / (kg * ºС); С2 (water) = 4200 J / (kg * ºС); L (water) = 2.3 * 10 ^ 6 J / kg.

η = (λ * m3 + ((C1 * m1 + C2 * (m2 + m3)) * Δt) + L * m) / (N * t).

m = (η * N * t – λ * m3 – ((C1 * m1 + C2 * (m2 + m3)) * Δt)) / L = (0.5 * 600 * 1800 – 3.4 * 10 ^ 5 * 0.2 – (920 * 0.2 + 4200 * (0.5 + 0.2)) * 100) / 2.3 * 10 ^ 6 = 0.0694 kg.



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