An aluminum sheet weighing 540 kg has a thickness of 5 mm. Determine the area of the sheet.
| July 2, 2021 | education
Initial data: m (weight of aluminum sheet) = 540 kg; h (thickness of the aluminum sheet) = 5 mm = 5 * 10-3 m.
Reference values: according to the condition ρ (aluminum density) = 2.7 g / cm3 or 2700 kg / m3.
1) Determine the volume of the aluminum sheet: V = m / ρ = 540/2700 = 0.2 m3.
2) Calculate the area of the aluminum sheet: V = S * h, whence S = V / h = 0.2 / (5 * 10-3) = 40 m2.
Answer: The area of the aluminum sheet is 40 m2.
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