An aluminum sheet weighing 540 kg has a thickness of 5 mm. Determine the area of the sheet.

An aluminum sheet weighing 540 kg has a thickness of 5 mm. Determine the area of the sheet. The density of aluminum is 2.7 g / cm3.

Initial data: m (weight of aluminum sheet) = 540 kg; h (thickness of the aluminum sheet) = 5 mm.

Constants: by the condition ρ (aluminum density) = 2.7 g / cm ^ 3 = 2700 kg / m ^ 3.

SI system: h = 5 mm = 5 * 10 ^ -3 m ^ 3.

1) Determine the volume of the aluminum sheet: V = m / ρ = 540/2700 = 0.2 m ^ 3.

2) We calculate the area of the aluminum sheet: V = S * h, whence S = V / h = 0.2 / (5 * 10 ^ -3) = 40 m ^ 2.

Answer: The area of this aluminum sheet is 40 m ^ 2.