An amount of electricity of 300 C passed through a conductor with a resistance of 20 Ohms in 5 minutes

An amount of electricity of 300 C passed through a conductor with a resistance of 20 Ohms in 5 minutes. Calculate the work of the current during this time.

Initial data: R (conductor resistance) = 20 Ohm; t (duration of current passage through the conductor) = 5 min; q (the amount of electricity passed through the conductor) = 300 Cl.

SI: t = 5 min = 5 * 60 s = 300 s.

The work of the current in 5 minutes can be determined by the formula: A = I ^ 2 * R * t = (q / t) ^ 2 * R * t = q ^ 2 * R / t.

Let’s calculate: A = 300 ^ 2 * 20/300 = 6000 J = 6 kJ.

Answer: In 5 minutes, the current will do a work of 6 kJ.