An amount of electricity of 300Kl passed through a conductor with a resistance

An amount of electricity of 300Kl passed through a conductor with a resistance of 20 ohms in 5 minutes. Calculate the work of the current during this time.

Given:

R = 20 Ohm – conductor resistance;

t = 5 minutes = 300 seconds – time span;

q = 300 Coulomb – the amount of electricity that has passed through the conductor over a period of time t.

It is required to determine A (Joule) – work amperage.

Let’s find the strength of the current passing through the conductor:

I = q / t = 300/300 = 1 Ampere.

Then the voltage will be equal to:

U = I * R = 1 * 20 = 20 Volts.

The power will be equal to:

W = U * I = 20 * 1 = 20 watts.

The work of the electric current will be equal to:

A = W * t = 20 * 300 = 6000 Joules.

Answer: the electric current did work equal to 6,000 Joules.