An apple fell from a 6m high tree. How long did it fall? What is the speed of the apple when it lands?

Traveled path of an apple when falling:
S = V0 * t + a * t² / 2, where S is the height of the fall of the apple (S = 20 m), V0 is the initial velocity of the apple (V0 = 0 m / s), t is the fall time of the apple (s), and – the acceleration with which the apple falls (a = g = 10 m / s²).
6 = 0 * t + 10 * t² / 2.
6 = 5 * t².
t = √ (6/5) = √ (1.2) ≈ 1.1 s.
Apple speed at the moment of falling:
V = V0 + g * t = 0 + 10 * 1.1 = 11 m / s.
Answer: The falling time of the apple is 1.1 s, the speed of the apple at the moment of falling is 11 m / s.