An arc of a circle AC that does not contain point B is 165 degrees. And the arc of a circle BC

An arc of a circle AC that does not contain point B is 165 degrees. And the arc of a circle BC that does not contain point A is 55 degrees. Find the inscribed corner ACB.

First way.
The degree measure of the full circle is 3600, then the degree measure of the arc AB = 360 – AC – BC = 360 – 165 – 55 = 140.
The inscribed angle ACB rests on the arc AB, then the angle ACB is equal to half the degree measure of the arc.
Angle ACB = 140/2 = 70.
Second way.
Inscribed angle ABC = AC / 2 = 165/2 = 82.5 inscribed angle BAC = BC / 2 = 55/2 = 27.5.
The sum of the inner angles of the triangle is 180, then the angle ACB = 180 – 82.5 – 27.5 = 70.
Answer: The ACB angle is 70.