An Archimedes force equal to 2700 N acts on a body immersed in water.
| April 26, 2021 | education
An Archimedes force equal to 2700 N acts on a body immersed in water. With what force would this body be pushed out by kerosene?
Data: Fa1 (Archimedes force in water) = 2700 N.
Reference values: ρw (fresh water density) = 1000 kg / m ^ 3; ρк (kerosene density) = 800 kg / m ^ 3.
The force of Archimedes, which acts on a body immersed in a liquid, can be determined by the formula: Fa = ρx * g * V.
Because g (acceleration due to gravity) and V (volume of a body immersed in a liquid) are constant, then the equality is true: Fa1 / ρв = Fa2 / ρк and Fa2 = Fa1 * ρк / ρв = 2700 * 800/1000 = 2160 N.
Answer: With kerosene, the body is pushed out with a force of 2160 N.
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