An arrow weighing 50 g is fired upward at a speed of 15 m / s. What is the maximum height it will rise to?

We have an initial velocity Vo = 15 m / s and an arrow mass m = 0.5 kg
Also we have g = 10 m / c ^ 2
Using the law of conservation of energy, we can find the height using this formula
Epo + Eko = Еp + Еk =) 0 + Еko = Еp + 0.
And it is equal
m * Vо2 / 2 = m * g * h
From this formula we derive the height
h = m * Vо2 / (2 * m * g) =) Vо2 / 2g
And just substitute the values
h = 15 ^ 2 / (2 * 10) = 11.25 m
Answer h = 11.25 m