An artificial earth satellite moves around it in a circular orbit at a speed of 7.8 km / h. Determine the satellite’s orbital

An artificial earth satellite moves around it in a circular orbit at a speed of 7.8 km / h. Determine the satellite’s orbital period if the satellite’s height above the Earth’s surface is 320 km

The satellite’s orbital period is found by the formula: T = 2πRearth / V = 2πRearth / Rearth and multiply all this by √ (Rearth + h) / g
Substitute the known values.
Rland = 6.371 × 10 ^ 6 m
T = 2 × 3.14 × 6.371 × 10 ^ 6 / 7.8 = 5.1 × 10 ^ 6 h