An astronaut weighing 72 kg pushes off the spacecraft skin and acquires a speed of 2 m / s.
| September 18, 2021 | education
An astronaut weighing 72 kg pushes off the spacecraft skin and acquires a speed of 2 m / s. What is the speed of the ship, if its mass is 2.6 tons?
mcosm = 72 kg.
Vcosm = 2 m / s.
mcorr = 2.6 t = 2600 kg.
Vcore -?
Let’s write down the law of conservation of momentum: mcosm * Vcosm = mcor * Vcor.
Vcor = mcosm * Vcosm / mcor.
Vcor = 72 kg * 2 m / s / 2600 kg = 0.055 m / s.
Answer: the speed of the ship will be Vcor = 0.055 m / s.
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