An athlete weighing 70 kg, jumping in height, acquires a speed of 6 m / s during the push for 0.3 s

An athlete weighing 70 kg, jumping in height, acquires a speed of 6 m / s during the push for 0.3 s / Determine the push force.

m = 70 kg.

t = 0.3 s.

V0 = 0 m / s.

V = 6 m / s.

F -?

The force F, which acts on the body, according to Newton’s 2 law, is equal to the product of the body’s mass m by its acceleration a: F = m * a.

The acceleration of the body is a vector quantity that shows how the velocity of the body changes over time t: a = (V – V0) / t.

F = m * (V – V0) / t.

Since the athlete starts his movement from the rest state V0, then F = m * V / t.

F = 70 kg * 6 m / s / 0.3 s = 1400 N.

Answer: the athlete’s pushing force when jumping is F = 1400 N.