An athlete weighing 80 kg, glides on skates. What is the pressure of an athlete on the ice if the length

An athlete weighing 80 kg, glides on skates. What is the pressure of an athlete on the ice if the length of one skate is 40 cm, width is 5 cm?

We start with the general pressure formula: P = F / S. There is no force, there is mass, we will write it as follows: F = mg. There is no area either, but it has the shape of a rectangle, so it can be found like this: S = l * d. Since there are two skates, the formula is as follows: P = P1 * 2. You probably made a mistake, the ridge should be 5mm wide. But I will decide on your terms. We translate the values into the SI system and substitute: P = 2 * mg / ld. P = 2 * 80 * 10 / 0.4 * 0.05 = 2 * 800 / 0.02 = 80000 (Pa) = 80kPa. In standard form = 8 * 10 ^ 4Pa.