An atom of an element contains three more electrons than a sodium ion. Determine the element
An atom of an element contains three more electrons than a sodium ion. Determine the element and calculate the number of atoms in a sample of a simple substance formed by this element if the sample mass is 5.4 g
We calculate the ordinal number of the element n (e) = n (Na) – 1 + 3 = 11 – 1 + 3 = 13.
Where n (Na) is the number of electrons in the sodium atom. In the formula above, we subtract one electron, since we are talking about a sodium ion – it has 1 less electron than an atom.
Aluminum has such a serial number and number of electrons.
Let us find the amount of aluminum substance ν (Al) = m (Al) / M (Al) = 5.4 / 27 = 0.2 mol, where m (Al) is the mass of aluminum, M (Al) is the molar mass of aluminum.
1 mole of a substance contains NA (Avogadro’s number) of its structural units (in our case, atoms). Let’s calculate the number of aluminum atoms N (Al) = ν (Al) * NA = 0.2 * 6.02 * 10 ^ 23 = 1.024 * 10 ^ 23