An atom passes from an excited state to a ground state, while emitting a photon. How will the energy of this photon

An atom passes from an excited state to a ground state, while emitting a photon. How will the energy of this photon, its frequency and wavelength change, if in the second case the atom goes over to the ground state with a higher energy than in the first case

If an atom passes into the ground state from a state with a higher energy, then the difference in the energies of these two states in the second case will be greater than in the first case. The energy of the emitted photon is equal to the difference between the energy of the two states: this means that the energy of the photon in the second case will be greater.
Since the frequency of a photon is proportional to its energy (from E = h * f), then in the second case the frequency of the photon will be higher.
The higher the frequency of the wave, the shorter its wavelength: l = c / f; hence, in the second case, the photon wavelength will be shorter than in the first case.