An electric charge of 3600 C flows through the conductor for an hour.

An electric charge of 3600 C flows through the conductor for an hour. Determine the time during which the 1200 C charge will flow at the same current.

The current (I) in a conductor is defined as the ratio of the charge (q) that passed through the cross-section of the conductor to the time (t) during which this charge passed, that is:

I = q / t.

In the first case I1 = q1 / t1, in the second I2 = q2 / t2. Since, according to the condition of the problem, I1 = I2, then:

q1 / t1 = q2 / t2.

In our case:

q1 = 3600 (Cl);

t1 = 1 (h) = 3600 (s);

q2 = 1200 (Cl);

it is necessary to determine t2.

With the last formula:

t2 = q2 * t1 / q1.

We make calculations:

t2 = q2 * t1 / q1 = 1200 * 3600/3600 = 1200 (s).

Answer: t2 = 1200 (s).