An electric cooker connected to a DC source consumes 108 kJ of energy in 120 seconds
| September 3, 2021 | education
An electric cooker connected to a DC source consumes 108 kJ of energy in 120 seconds. What is the current strength in the spiral of the tile, if its resistance is 25 ohms?
The current strength in the spiral of an electric tile can be calculated using the Joule-Lenz law:
Q = I ^ 2 * R * t, where according to the condition Q (energy consumption) = 108 kJ = 108 * 10 ^ 3 J, R (electric hotplate spiral resistance) = 25 Ohm, t (hotplate operation time) = 120 s …
I2 = Q / (R * t) and I = √ (Q / (R * t)).
Let’s do the calculation:
I = √ (108 * 10 ^ 3 / (25 * 120)) = √36 = 6 A.
Answer: The current in the coil of an electric hotplate is 6 A.
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