An electric current of 20 A was passed for 600 seconds through the aqueous CuSO4 solution.

An electric current of 20 A was passed for 600 seconds through the aqueous CuSO4 solution. What substances and in what quantity will be released during this time on the carbon electrodes? Write down the equations of the anodic and cathodic processes, as well as the total equation of electrolysis.

Given:
I = 20 A
t = 600 s
F = 96485 C / mol

To find:
m (in-in on the electrodes) -?

Decision:
1) Write the reaction equation:
CuSO4 <=> Cu2 + + SO42-;
К (-): Cu2 + + 2е => Cu0;
A (+): 2H2O – 4e => O20 + 4H +;
2CuSO4 + 2H2O = (electric current) => 2Cu + 2H2SO4 + O2 ↑;
2) Calculate the mass of Cu:
m (Cu) = M (Cu) * I * t / (N (e) * F) = 64 * 20 * 600 / (2 * 96485) = 3.98 g;
3) Calculate the mass of O2:
m (O2) = M (O2) * I * t / (N (e) * F) = 32 * 20 * 600 / (4 * 96485) = 0.99 g.

Answer: The mass of Cu is 3.98 g; O2 – 0.99 g.