An electric iron with a power of 0.66 kW was included in the 220 V network. What is the resistance of the heating element

An electric iron with a power of 0.66 kW was included in the 220 V network. What is the resistance of the heating element of this iron? how much heat will be released by the heating element of this iron in 10 minutes?

Let’s use the formula for the power in the electrical circuit:

P = U ^ 2 / R, where P is power, U is voltage, R is resistance.

Then:

R = U ^ 2 / P.

We substitute the values specified in the problem into the resulting formula:

R = 220 ^ 2/660 = 220/3 = 73 ohms.

The released heat is determined by the formula:

Q = P * t, where t is time.

Time must be expressed in seconds:

10 minutes = 10 * 60 = 600 s.

Q = 73 * 600 = 44000 J = 44 kJ

Answer: the required resistance and the amount of heat will be 73 Ohm and 44 kJ.