An electric kettle with a power of 1150 W contains 0.6 kg of water. How long after boiling will all the water

An electric kettle with a power of 1150 W contains 0.6 kg of water. How long after boiling will all the water from the kettle boil away? Specific heat of vaporization of water 2300 kJ / kg

Initial data: N (power of the electric kettle) = 1150 W, m (mass of water in the kettle) = 0.6 kg.

Reference values: according to the condition L (specific heat of vaporization of water) = 2300 kJ / kg (2300 * 10 ^ 3 J / kg).

The time when the water can completely boil out of the kettle is determined from the equality: N * t = L * m, whence t = L * m / N.

Let’s make the calculation: t = 2300 * 10 ^ 3 * 0.6 / 1150 = 1200 s (20 min).

Answer: The water will completely boil out of the kettle in 20 minutes.