An electric lamp with a current of 0.6 amperes is included in a 127 volt circuit. Find the current in the lamp.

Since the electric power of the electric lamp, which is released in the section of the electric circuit, will be equal to the product of the voltage in the network and the current strength, then: P = U * I, where U = 127 V, I = 0.6 A.
Let’s calculate the electrical power:
P = U * I = 127 * 0.6 = 76.2 W.
Check: W = B * A = W.
Answer. The current power in the lamp is 76.2 W.