An electric lamp with a power of 36 W is designed for a voltage of 12 V. Determine the amperage in the lamp.

The given tasks: P (power of the taken electric lamp) = 36 W; U (rated voltage across the lamp) = 12 V.

We express the strength of the electric current in the lamp from the formula for calculating the power: P = U * I, whence I = P / U.

Calculation: I = 36/12 = 3 A.

Answer: A current of 3 A flows through the lamp.



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