# An electric light bulb and a resistor are connected in series in the network. The resistance of the filament

May 28, 2021 | education

| **An electric light bulb and a resistor are connected in series in the network. The resistance of the filament of the bulb is 14 ohms, and the resistor is 480 ohms. What is the voltage across the resistor if the voltage across the bulb is 3.5V?**

Given:

r1 = 14 Ohm,

r2 = 480 Ohm,

U1 = 3.5V;

Find: U2 -?

When two consumers of electricity are connected in series, the same current flows through them.

The current can be found from Ohm’s law:

I = U1 / r1 = 3.5 / 14 = 0.25A.

From the same Ohm’s law, we find the voltage across the resistor:

U2 = I * r2 = 0.25 * 480 = 120V.

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