An electric motor of voltage at the terminals of which is equal to 24V for 5 world has done work of 36 kJ.

An electric motor of voltage at the terminals of which is equal to 24V for 5 world has done work of 36 kJ. Determinant of the current strength in electric motors. Do not count losses.

U = 24 V.
t = 5 min = 300 s.
A = 36 kJ = 36000 J.
I -?
The work of the electric current, A, is determined by the Joule-Lenz law: A = I * U * t, where I is the current in the conductor, U is the voltage at the ends of the conductor, t is the time of passage of the current.
We find the current in the motor by the formula: I = A / U * t.
I = 36000 J / 24 V * 300 s = 5 A.
Answer: in the winding of an electric motor, the current strength is I = 5 A.